Arithmetic Mean (Discrete Series)- Direct and Short-cut Method Solved Examples
Arithmetic Mean
Discrete Series
Direct Method- To find out the total of items in discrete series, frequency of each value is multiplied with the respective size. The values so obtained are totaled up. This total is then divided by the total number of frequencies to obtain the arithmetic mean.
Question 1(a): Calculate mean from the following data by using direct
method.
Value: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
Frequency: 21, 30, 28, 40, 26, 34, 40, 9, 15, 57
|
Value (x) |
Frequency (f) |
fx |
|
1 |
21 |
21 |
|
2 |
30 |
60 |
|
3 |
28 |
84 |
|
4 |
40 |
160 |
|
5 |
26 |
130 |
|
6 |
34 |
204 |
|
7 |
40 |
280 |
|
8 |
9 |
72 |
|
9 |
15 |
135 |
|
10 |
57 |
570 |
|
|
N = 300 |
∑fx = 1716 |
Question 1(b): Calculate mean from the following data by using short cut
method.
Value: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
Frequency: 21, 30, 28, 40, 26, 34, 40, 9, 15, 57
|
Value (x) |
Frequency (f) |
A = 6 d (X - A) |
fd |
|
1 |
21 |
-5 |
-105 |
|
2 |
30 |
-4 |
-120 |
|
3 |
28 |
-3 |
-84 |
|
4 |
40 |
-2 |
-80 |
|
5 |
26 |
-1 |
-26 |
|
6 |
34 |
0 |
0 |
|
7 |
40 |
1 |
40 |
|
8 |
9 |
2 |
18 |
|
9 |
15 |
3 |
45 |
|
10 |
57 |
4 |
228 |
|
|
N = 300 |
|
∑fd = -84 |
Question 2(a): Calculate mean from the following data by using direct
method.
Marks: 52
58 60 65
68 70 75
No. of Students: 5 3
2 4 1
1 2
|
No. of Students [f] |
Marks [x] |
fx |
|
5 |
52 |
260 |
|
3 |
58 |
174 |
|
2 |
60 |
120 |
|
4 |
65 |
260 |
|
1 |
68 |
68 |
|
1 |
70 |
70 |
|
2 |
75 |
150 |
|
N=18 |
|
∑fx = 1102 |
Question 2(b): Calculate mean from the following data by using short cut
method.
Marks: 52
58 60 65
68 70 75
No. of Students: 5 3 2 4 1 1 2
|
Marks [x] |
No. of Students [f] |
A=60 d=[X-A] |
fd |
|
52 |
5 |
-8 |
-40 |
|
58 |
3 |
-2 |
-6 |
|
60 |
2 |
0 |
0 |
|
65 |
4 |
5 |
20 |
|
68 |
1 |
8 |
8 |
|
70 |
1 |
10 |
10 |
|
75 |
2 |
15 |
30 |
|
|
N=18 |
|
∑fd =22 |
Question 3(a): Calculate mean from the following data by using direct
method.
Student’s Age [x]: 20, 23, 25, 28, 30
No. of Students [f]: 3, 5, 10, 6, 1
|
Student’s Age [x] |
No. of Students [f] |
fx |
|
20 |
3 |
60 |
|
23 |
5 |
115 |
|
25 |
10 |
250 |
|
28 |
6 |
168 |
|
30 |
1 |
30 |
|
|
N=25 |
∑fx = 623 |
Question 3(b): Calculate mean from the following data by using short cut
method.
Student’s Age [x]: 20 23
25 28 30
No. of Students [f]: 3 5
10 6 1
|
Student’s Age [x] |
No. of Students [f] |
A= 25 D=[x-A] |
fd |
|
20 |
3 |
-5 |
-15 |
|
23 |
5 |
-2 |
-10 |
|
25 |
10 |
0 |
0 |
|
28 |
6 |
3 |
18 |
|
30 |
1 |
5 |
5 |
|
|
N=25 |
|
∑fd = -2 |
Question 4(a): Calculate mean from the following data by using direct
method.
The coins are tossed 1024 times. The theoretical frequencies of 10
heads, 9 heads, …0 heads are given below:
No. of heads: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
Frequency: 1 10 45 120 210 252 210 120 45 10 1
|
No. of heads [x] |
Frequency [f] |
fx |
|
0 |
1 |
0 |
|
1 |
10 |
10 |
|
2 |
45 |
90 |
|
3 |
120 |
360 |
|
4 |
210 |
840 |
|
5 |
252 |
1260 |
|
6 |
210 |
1260 |
|
7 |
120 |
840 |
|
8 |
45 |
360 |
|
9 |
10 |
90 |
|
10 |
1 |
10 |
|
|
N=1024 |
∑fx =5120
|
Question 4(b): Calculate mean from the following data by using direct method.
The coins are tossed 1024 times. The theoretical frequencies of 10 heads, 9 heads, …0 heads are given below:
No. of heads: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
Frequency: 1 10 45 120 210 252 210 120 45 10 1
|
No. of heads [x] |
Frequency [f] |
A=5 d=[x-A] |
fd |
|
0 |
1 |
-5 |
-5 |
|
1 |
10 |
-4 |
-40 |
|
2 |
45 |
-3 |
-135 |
|
3 |
120 |
-2 |
-240 |
|
4 |
210 |
-1 |
-210 |
|
5 |
252 |
0 |
0 |
|
6 |
210 |
1 |
210 |
|
7 |
120 |
2 |
240 |
|
8 |
45 |
3 |
135 |
|
9 |
10 |
4 |
40 |
|
10 |
1 |
5 |
5 |
|
|
N=1024 |
|
∑fd = 0 |
Question 5(a): Calculate mean from the following data by using direct
method.
Values: 0 1 2 3 4 5 6
7 8 9 10
Frequency: 4 10 41 131 105 158 211 118 52 7 2
|
Values [x] |
Frequency [f] |
fx |
|
0 |
4 |
0 |
|
1 |
10 |
10 |
|
2 |
41 |
82 |
|
3 |
131 |
393 |
|
4 |
105 |
420 |
|
5 |
158 |
790 |
|
6 |
211 |
1266 |
|
7 |
118 |
826 |
|
8 |
52 |
416 |
|
9 |
7 |
63 |
|
10 |
2 |
20 |
|
|
N=839 |
∑fx =4286 |
Values: 0 1 2 3 4 5 6 7 8 9 10
Frequency: 4 10 41 131 105 158 211 118 52 7 2
|
Values [x] |
Frequency [f] |
A-5 d=[x-A] |
fd |
|
0 |
4 |
-5 |
-20 |
|
1 |
10 |
-4 |
-40 |
|
2 |
41 |
-3 |
-123 |
|
3 |
131 |
-2 |
-262 |
|
4 |
105 |
-1 |
-105 |
|
5 |
158 |
0 |
0 |
|
6 |
211 |
1 |
211 |
|
7 |
118 |
2 |
236 |
|
8 |
52 |
3 |
156 |
|
9 |
7 |
4 |
28 |
|
10 |
2 |
5 |
10 |
|
|
N=839 |
|
∑fd=91 |












Thanks a lot Mam.
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